Minimum Number of Steps to Make Two Strings Anagram II - Frequency map
Solution: Two Frequency Arrays
Solution: Two Frequency Arrays
Use two arrays of size 26 to store the frequency of each character in s and t.
Return the sum of the absolute differences between each sFreq[i] and tFreq[i].
n = s.length, m = t.length
Time Complexity: O(n + m)
Space Complexity: O(1)
var minSteps = function(s, t) {
let sFreq = Array(26).fill(0), tFreq = Array(26).fill(0);
for (let char of s) sFreq[char.charCodeAt() - 97]++;
for (let char of t) tFreq[char.charCodeAt() - 97]++;
let ans = 0;
for (let i = 0; i < 26; i++) {
ans += Math.abs(sFreq[i] - tFreq[i]);
}
return ans;
};
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